Parallel Forces: Painter on scaffold x meters from 1 end.

  • Thread starter Thread starter Ocata
  • Start date Start date
  • Tags Tags
    Forces Parallel
AI Thread Summary
The discussion centers on the concept of choosing any point as a center of rotation in a torque problem involving a painter on a scaffold. The example illustrates how to calculate the forces at each end of a 6ft scaffold when a 150lb painter stands 2ft from one end, resulting in F1 being 100lbs and F2 being 50lbs. The question arises about the implications of selecting different points of rotation and whether there are infinite or finite choices for these points. It is noted that regardless of the chosen point, the forces must still balance according to the principles of torque. The discussion emphasizes the flexibility in selecting a center of rotation while maintaining the equilibrium of forces.
Ocata
Messages
198
Reaction score
5
Hi,

My book says that although there is a natural point of rotation, we can however choose any point as a center of rotation. But without explaining further, it goes directly to an example where the endpoint is the center of rotation.

I would like to know what the book means by being able to choose any point as a center of rotation.

For example,
A painter weighing 150lbs is standing on a 6ft scaffold at a distance of 2 ft from one end. How much weight must each end of the scaffold hold?

F1 + F2 = 150lbs

Torque = Torque
Fs = Fs
150lbs(2ft) = F2(6ft)
F2 = 50lbs

So F1 + F2 = 150lbs
F1 + 50lbs = 150lbs
F1 = 100lbs

Here, F1 was the point of rotation. But how can this problem be approached if a different point of rotation is considered? And is there an infinite number of choices for points of rotation? Or is there a finite number of possible points/centers of rotation?
 
Physics news on Phys.org
Let's say you chose a point of rotation on the scaffold, 0<x<6.
Then if F1 is placed at 0 and F2 placed at 6, you still have to balance the forces.
 
  • Like
Likes Ocata
Thank you RUber.
 
Thread 'Question about pressure of a liquid'
I am looking at pressure in liquids and I am testing my idea. The vertical tube is 100m, the contraption is filled with water. The vertical tube is very thin(maybe 1mm^2 cross section). The area of the base is ~100m^2. Will he top half be launched in the air if suddenly it cracked?- assuming its light enough. I want to test my idea that if I had a thin long ruber tube that I lifted up, then the pressure at "red lines" will be high and that the $force = pressure * area$ would be massive...
I feel it should be solvable we just need to find a perfect pattern, and there will be a general pattern since the forces acting are based on a single function, so..... you can't actually say it is unsolvable right? Cause imaging 3 bodies actually existed somwhere in this universe then nature isn't gonna wait till we predict it! And yea I have checked in many places that tiny changes cause large changes so it becomes chaos........ but still I just can't accept that it is impossible to solve...
Back
Top