Point A (3,2,-1) is equidistant from two planes (parallel), known as P1 and P2. P1 has the equation 2x-y+2z+4 = 0. Find the equation of P2.
D = abs val(ax_o + by_o + cz_o + d) divided by sqrt (a^2 + b^2 + c^2)
The Attempt at a Solution
I used the distance formula and figured out that the distance between the point and either plane is 2. But what do I do now? I know that the plane I'm looking for, since it's parallel, has a perpendicular vector that is the same as P1, if not a scalar multiple. But what next? Thanks in advance.