Parallel plate conductors of opposing charge and unequal magnitude

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SUMMARY

The discussion focuses on calculating the electric field (E field) between two parallel plate conductors with opposing charge densities of σ and -5σ, separated by a distance x. The E field at the midpoint (x/2) can be determined using Gauss's law, which allows for the calculation of the field due to uniform planar charge densities. The principle of superposition applies, meaning the contributions from both plates should be added together to find the resultant E field. The electric field will not be constant between the plates due to the unequal magnitudes of charge.

PREREQUISITES
  • Understanding of Gauss's law
  • Knowledge of electric fields generated by planar charge distributions
  • Familiarity with the concept of superposition in electrostatics
  • Basic principles of parallel plate capacitors
NEXT STEPS
  • Study the application of Gauss's law for different charge distributions
  • Learn about the electric field calculations for non-uniform charge densities
  • Explore the concept of electric field superposition in more complex geometries
  • Investigate the behavior of electric fields in capacitors with unequal charge magnitudes
USEFUL FOR

Students preparing for physics exams, particularly those focusing on electrostatics, as well as educators seeking to enhance their understanding of electric fields in capacitor systems.

JJK1503
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A question has occurred to me during preparation for a Physics exam. My textbook does a good job of discussing a capacitor charged equal but opposite. But I want to take it a step further. My question is how to calculate the E field between 2 plates of opposing charge that have unequal magnitudes.

For example; if I have two plates of σ and -5σ a distance x apart, what would the E field be at x/2 ? Would the magnitude of the E field be constant for any point between the plates, as it is with a capacitor? Is this a simple superposition problem where I should create a Gaussian cylinder and find E field for both adding them together or is it something else? I am definitely over thinking this one.

I feel like this is exactly the type of curve ball my professor might throw at us on Monday. Any help is much appreciated. I have spent too much time thinking about this.
 
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JJK1503 said:
A question has occurred to me during preparation for a Physics exam. My textbook does a good job of discussing a capacitor charged equal but opposite. But I want to take it a step further. My question is how to calculate the E field between 2 plates of opposing charge that have unequal magnitudes.

For example; if I have two plates of σ and -5σ a distance x apart, what would the E field be at x/2 ? Would the magnitude of the E field be constant for any point between the plates, as it is with a capacitor? Is this a simple superposition problem where I should create a Gaussian cylinder and find E field for both adding them together or is it something else? I am definitely over thinking this one.

Welcome to PF !

Assuming you are talking about a parallel plate capacitor ,the charges on the inner surfaces of the two plates would be equal and opposite .This in turn means that there would be charges on the outer surfaces of the two plates .

Regarding the magnitude of the charges on the inner surfaces and on the outer surfaces , you need to use the condition that electric field inside the conductor is zero .
 
You should be able to calculate the field of a uniform planar charge density using Gauss's law.
Simply add the contributions at x/2 of two such planes with sigma and -5 sigma.
 

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