Parallel RC Circuits: Charging to 0.75V in Seconds

AI Thread Summary
In a parallel RC circuit with a 0.1M Ω resistor and a 10 μF capacitor connected to a 1.5 V source, the voltage across the capacitor will reach 1.5 V almost instantaneously due to the negligible resistance of the source. The time constant for charging is effectively zero, leading to the conclusion that the capacitor charges to 0.75 V in zero seconds. The discussion confirms that the capacitor does not take time to charge in this specific setup. Therefore, the correct answer to the problem is zero seconds. This highlights the impact of negligible resistance in parallel circuits on charging times.
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Homework Statement



A parallel combination of 0.1M Ω resistor and a 10 μF capacitor is connected across a 1.5 V source of negligible resistance. The time (in seconds) required for the capacitor to get charged upto 0.75 V is approximately

(A) ∞
(B) ln 2
(C) log 2
(D) Zero

Homework Equations



##V = V_0(1-e^{\frac{-t}{RC}})##

The Attempt at a Solution



So, V0 should be 1.5 V, and C is 10 μF. However, should't the voltage across the capacitor be 1.5 V at all times because it's in parallel with the resistance? Even if I use Thevenin's theorem, I get the resistance across the capacitor as 0 ⇒ time constant is 0. Please help?
 
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If the 1.5 V source has negligible resistance then your Thevenin idea is correct and the circuit's time constant will be correspondingly negligible (effectively zero seconds). So how long will it take to fully charge the capacitor from 0 V to 1.5 V?
 
Zero, so that should be the answer.
 
Yup.
 
Thanks!
 
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