1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Parallel RLC circuit phasor diagram

  1. Dec 18, 2011 #1
    I am having difficulties with phasor diagram for Is and Vs of an parallel RLC circuit. I have calculated all values but not sure how to use phasors.
    Impedance Z has angle +65°. Current Isupply +30° and Vsupply is Z*Is= Vs at angle 95°
    But with parrallel network V is the reference so I guess it could be horizontal line.
    Is Isupply 30° from virtual horizonatl reference line, and Vs 95 degrees from virtual horizonatl line, therefore the difference between these two would be 65 degrees with voltage leading?
    Any help is welcome
     
  2. jcsd
  3. Dec 18, 2011 #2

    NascentOxygen

    User Avatar

    Staff: Mentor

    It's a bit of a mystery how you got those three angles. Normally, I or V is taken as the reference zero angle, but you seem to have used some other undisclosed voltage or current as your zero degree reference.

    Yes. So you'd have V at 0 degrees. You say Z has been calculated inductive at +65 degrees. So this means I=V/Z giving I an angle of -65 degrees.

    In summary, it's V at 0. Z at +65. I at -65. You of course need the degree symbols here, but this browser is broken and doesn't allow me to insert symbols.

    So check what you have done, and try and figure out what that 30 degrees associated with the current is. I can't explain it. Perhaps there are other elements in your circuit?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Parallel RLC circuit phasor diagram
  1. RLC Parallel Circuit (Replies: 4)

Loading...