Parallel Vectors: Solving for a

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To determine the value of a for which the vectors u=<2,4,-5> and v=<-4,-8,a> are parallel, the cross product must equal zero. The initial attempt at solving the cross product yielded an incorrect k-hat component, which needs correction. A more straightforward method involves setting u equal to a scalar multiple of v, expressed as u = λv, to find a single solution for λ and a. This approach simplifies the process of identifying the conditions for parallelism between the two vectors. The discussion emphasizes the importance of correctly calculating the cross product and exploring alternative methods for solving the problem.
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Homework Statement



for what value of a will the vectors u=<2,4,-5> and v=<-4,-8,a>

Homework Equations



(uXv)=0

The Attempt at a Solution


i took the cross product and got 4(a-10)i-2(a-10)j-32k=0

i don't know wher eto go from there do i set a-10=0 solve for a so my answer is ten?
 
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You didn't finish writing the problem statement.
 
Assuming you're trying to find which values of a make the two vectors parralell...

the k-hat component isn't right in what you've posted, and once you get that it's pretty straightforward to find the values of a so that's you get the zero vector as the cross product.
 
Hi MozAngeles! :smile:

There is an easier way to find 2 parallel vectors.
If u and v are parallel, one must be a multiple of the other.

That is, if you try to solve:

u = λv

that should have a single solution for λ and a.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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