Parametric Paraboloid In Polar Coordinates

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Homework Help Overview

The discussion revolves around finding a parametric representation of a paraboloid defined by the equation z = x² + y², specifically within the bounds of z = 0 to z = 1. The original poster explores the use of polar coordinates to express this paraboloid parametrically.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to define a parametric form using polar coordinates, while some participants question the clarity and correctness of this approach, suggesting that it may still reflect Cartesian coordinates. Others clarify the use of polar coordinates in the xy-plane and discuss the terminology related to cylindrical coordinates.

Discussion Status

The discussion is active, with participants providing feedback on the original poster's approach and terminology. There is a mix of interpretations regarding the use of polar versus cylindrical coordinates, indicating a productive exploration of the topic without reaching a consensus.

Contextual Notes

Participants are navigating the definitions and applications of coordinate systems in three-dimensional space, particularly in relation to the paraboloid's parametric representation. The original poster acknowledges a potential misunderstanding in terminology, which adds to the complexity of the discussion.

Lancelot59
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I just want to see if my logic is sound here. If we have the paraboloid z=x2+y2 from z=0 to z=1, and I wanted a parametric form of that I think this should work for polar coordinates:

[tex]\vec{r}(u,v)=(vcosu,vsinu,v^{2})[/tex]
[tex]u:[0..2\pi],v:[0..1][/tex]

Does this make sense?
 
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not really i think you are still defining cartesian coords, though its not exactly clear what you are trying to do
 
Last edited:
Thise are perfectly good parametric equations for the paraboloid, using "polar coordinates" in the xy-plane as parameters (actually you are using v= r, [itex]u= \theta[/itex]).
 
ok, so parameterise in terms of 2D polar coords, that makes more sense
 
Then it isn't in 3D anymore...I meant to say cylindrical coordinates, so that's my bad with the terminology.
 

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