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Homework Statement
I have an initial data of d= 0.012608, V = 320 volt, Q = 1.50e-8 and A = 1.25e-4. y = Qd/AV. what is Δy , the partial derivative of y with respect to d?
The discussion focuses on calculating the partial derivative of the function y = Qd/AV with respect to the variable d, given the constants Q = 1.50e-8, A = 1.25e-4, and V = 320 volts. The correct approach involves treating the constant term Q/AV as a constant during differentiation. The result of the partial derivative is \(\frac{\partial y}{\partial d} = \frac{Q}{AV}\), which simplifies to \(\frac{1.50e-8}{1.25e-4 \cdot 320}\) when substituting the values.
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