- #1
chaotixmonjuish
- 287
- 0
I borrowed this book form the library to get a heads up on what i would be doing in PDEs and it had this equation
xUx+yUy=nu
and its solution (according to the back) is: u(x,y)=xnf(y/x)
I did figure out the f(y/x) part:
dx/x=dy/y
ln(x)+c=ln(y)
cx+y
c=y/x
how did the xn come into play
xUx+yUy=nu
and its solution (according to the back) is: u(x,y)=xnf(y/x)
I did figure out the f(y/x) part:
dx/x=dy/y
ln(x)+c=ln(y)
cx+y
c=y/x
how did the xn come into play