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Partial differential problem in introductory tensor analysis

  1. Nov 8, 2012 #1
    So far I have only seen ∂/(∂y) as being interpreted as an operator being of no use unless it is applied to some vector etc.

    Now, however, my course literature asserts the following equality:


    What is the interpretation of the differentials in this case?
  2. jcsd
  3. Nov 9, 2012 #2
    I suppose is a short way to express [itex]\frac{\partial \psi}{\partial y}=y\psi[/itex].
  4. Nov 15, 2012 #3
    Yes, that is a correct statement, but it relies on the asserted equality, so unfortunately it brings nothing new to the party. Luckily I have it all figured out by now, so I thank you for your answer and continue my studies. :)
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