Partial differentiation question?

Click For Summary
SUMMARY

The coefficient of rigidity \( n \) for a wire is defined by the formula \( n = \frac{AL}{d^4} \). In this discussion, the user successfully calculated the maximum possible error in \( n \) as ±4.25% after considering measurement errors of ±0.25% for length \( L \) and ±1% for diameter \( d \). The user initially struggled with the differentiation process but resolved the issue by including the correct units in their calculations.

PREREQUISITES
  • Understanding of partial differentiation
  • Familiarity with error analysis in measurements
  • Knowledge of the physical properties of materials, specifically rigidity
  • Basic algebra and unit conversion skills
NEXT STEPS
  • Study advanced techniques in partial differentiation
  • Research error propagation methods in physical measurements
  • Explore the relationship between rigidity and material properties
  • Learn about the applications of rigidity coefficients in engineering
USEFUL FOR

Students in physics or engineering, researchers in material science, and professionals involved in mechanical design and analysis.

cowboi12345
Messages
7
Reaction score
0
The coefficient of rigidity n of a wire of length L and uniform diameter is given by:
n = AL/d^4

where A is a constant...If errors of +- 0.25% and +-1% are possible in measuring L and d respectively, find the maximum possible error in the calculated value of n...

how do i do this.?

I've partially differentiated it with respect to L and d...and that's about it..
 
Physics news on Phys.org
ok...nvm...i got it...its +-4.25%...i forgot to include the units of 0.25L and 1d...lol...
 

Similar threads

Replies
10
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K