Partial Fraction Decomposition for Integrating Rational Functions

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SUMMARY

The discussion focuses on integrating the rational function (sec(t)^2) / (tan(t)^3 + tan(t)^2) using partial fraction decomposition. The user correctly transformed the integral into the form 1 / (u^3 + u^2) with u = tan(t) but struggled to proceed. The solution involves applying partial fraction decomposition to the expression 1 / (u^2(u+1)), which can be expressed as A/u^2 + B/(u+1) + C/u. The user is advised to persist with this method rather than resorting to integration by parts.

PREREQUISITES
  • Understanding of rational functions and their integrals
  • Familiarity with the concept of partial fraction decomposition
  • Knowledge of basic calculus, specifically integration techniques
  • Ability to manipulate algebraic expressions involving variables
NEXT STEPS
  • Study the method of partial fraction decomposition in detail
  • Practice integrating rational functions using various techniques
  • Explore the application of integration by parts in different contexts
  • Review algebraic manipulation techniques for simplifying expressions
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Students and educators in calculus, mathematicians focusing on integration techniques, and anyone seeking to enhance their understanding of rational function integration.

JamesGoh
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Im trying to find the integral of ( sec(t)^2 ) / ( (tan(t)^3) + (tan(t)^2) ). I've managed to get the
integral into the form

1 / (u^3 + u^2) where u = tan(t), however I am having difficulty proceeeding from there.

Could someone take a look at the working out I have attached and let me know what I am not doing right? (the correct answer is written in red pen on 2nd page)
 

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In order to evaluate ##\int\frac{1}{u^2(u+1)}\ du##, you want to use partial fraction decomposition, and that alone. You do not need to do any integration by parts. You have a correct general form $$\frac{1}{u^2(u+1)}=\frac{A}{u^2}+\frac{B}{u+1}+\frac{C}{u}$$ for the PFD, but then it looks like it all goes south after that, and you just gave up on that idea. Stick with that Idea.
 

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