1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Partial Fraction Decomposition

  1. Mar 31, 2014 #1
    1. The problem statement, all variables and given/known data
    use partial fraction decomposition to re-write 1/(s2(s2+4)




    3. The attempt at a solution
    I thought it would break down into (A/s) + (B/s2) + ((cx+d)/(s2+4)
    but it doesn't.
     
  2. jcsd
  3. Mar 31, 2014 #2

    Mark44

    Staff: Mentor

    The only thing wrong is that the last term should be (cs + d)/(s2 + 4). Otherwise, your decomposition is correct.
     
  4. Mar 31, 2014 #3
    Okay, thank you sir.
     
  5. Apr 1, 2014 #4
    okay I had this problem solved, but I went back after changing my variable from x to s
    and I get A(s)(s2+4) + B(s2+4) +(cs+d)(s2) = 1 (1)
    if I let s = 0 then B(4) = 1 -> B = 1/4
    if I let s = +/-2i then +/-2iC + D = -1/4 (2)
    where as before I equate coefficients it's obvious to me that +/-2iXC != -1/4 and D = -1/4 so C = 0
    Letting s = 1 after I get A = 0 also,
    my questions are how do I come to the conclusion that C = 0 in (2)? Should I keep plugging values into (1) and try to create a system? Also, how do I pick values for A, once I've actually calculated D, C, and B. What would cause me to choose 1 for S as opposed to any other value?
     
  6. Apr 1, 2014 #5

    Ray Vickson

    User Avatar
    Science Advisor
    Homework Helper

    Just write ##s^2 = x##, so you have
    [tex] \frac{1}{x(x+4)}[/tex]
    The partial fraction expansion for this is
    [tex] \frac{1}{4x} - \frac{1}{4(x+4)},[/tex]
    and you can now put back ##x = s^2## to get
    [tex] \frac{1}{4 s^2} - \frac{1}{4(s^2+4)}[/tex]
    If you want, you can even introduce complex numbers and bread this down further into
    [tex] \frac{1}{4s^2} +\frac{1}{16 i (s - 2i)} - \frac{1}{16 i (s + 2i)}[/tex]
    where ##i = \sqrt{-1}##.
     
  7. Apr 1, 2014 #6
    wow, very cool. I've never done it like that before. Thanks a lot
     
  8. Apr 1, 2014 #7

    Mark44

    Staff: Mentor

    Because -1/4 has no imaginary part. You can think of your equation as being written like this:
    D + 2Ci = -1/4 + 0i
    From this we see that D = -1/4 and C = 0.
    It doesn't matter what values you choose for s. The only thing to be concerned with is how convenient a particular value is.

    The equation you started with -- A/s + B/s2 + (Cs + D)/(s2 + 4) -- has to be identically true. IOW, it has to be true for all values of s. Any four values you choose will give you four equations for the unknowns A, B, C, and D. The strategy is to pick values so that some of the terms go away, making your task of solving the system easier.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Partial Fraction Decomposition
Loading...