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I need to find the partial fraction expansion of the integrand z/[(z-2i)(z+i)]
Just doing 1/(z-2i) + 1/(z+i) results in (2z-i)/(z-2i)(z+i).
It seems easy, but I can't figure out what to multiply by to get the correct numerator.
Just doing 1/(z-2i) + 1/(z+i) results in (2z-i)/(z-2i)(z+i).
It seems easy, but I can't figure out what to multiply by to get the correct numerator.