1. The problem statement, all variables and given/known data Find the exact values of A, B, and C in the following partial fraction decomposition.Then obtain the integral using those values. 1/(x^3-3x^2) = A/x + B/x^2 + C/(x-3) 2. Relevant equations I'm not sure at this point. 3. The attempt at a solution To make the denominator on the right equal to the left... A(x^2)(x-3) + B(x)(x-3) + C(x)(x^2) so..... 1 = Ax^3 +Cx^3 -3Ax^2 +Bx^2 -3Bx From cubic values.. A + C = 0 So A= -C From squared values... -3A + B = 0 So A = 1/3B which also means C = -1/3B From x values.. -3B = 0. Here is where im at a loss. The x value equation cannot possibly be correct. It would denote that B=0, therefore A and C also equal 0. Am I doing something incorrectly in my multiplication? If not, how is it possible to use the partial fractional decomposition method to make an equation for integration?