Partial Fractions problem, need some guidance.

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SUMMARY

The discussion centers on solving the partial fraction decomposition of the expression \(\frac{gx^2+1}{x^3(x-1)^2}\). The user successfully determined that \(E = g + 1\) by substituting \(x = 1\) and found \(C = 1\) using \(x = 0\). The solution involves multiplying out the polynomials and equating coefficients, leading to the equation \(A + D = 0\) for the \(x^4\) terms. The user is guided to find the remaining coefficients \(A\), \(B\), and \(D\) through substitution without the need for matrices.

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Homework Statement



[tex]\frac{gx^2+1}{x^3(x-1)^2}[/tex]

I'm trying to keep g as a coefficient, it's turning into a mess though.

The Attempt at a Solution



After I broke it down it gives:

[tex]Ax^2(x-1)^2 + Bx(x-1)^2 + C(x-1)^2 + Dx^3(x-1) + Ex^3 = gx^2 + 1[/tex]

After using x =1, everything goes away and I'm left with E = g + 1.

Then I used x = 0, which gave C = 1.

After that, I'm stuck. At this point I wish I knew more about linear algebra. Is there anyway to do this without going nuts with matrices? Thanks for any help.
 
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I would multiply all of the polynomials out and equate the coefficients on both sides.

For instance, after multiplying all of the polynomials, you will see an Ax4 term and a Dx4 term. Since there is no x4 term on the RHS you can say that
A + D = 0.

You'll come up with four more equations, one of which you already got (C = 1). You can then find the remaining values of A, B, D, and E via substitution. No matrices needed! :wink:
 

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