Particle Energy on a Smooth Sphere: Finding the Point of Departure

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A particle placed on a smooth sphere at a distance of b/2 above the central plane will leave the sphere when the normal force becomes zero, meaning only gravitational force acts on it. To determine the departure point, the centripetal component of gravitational force must be expressed as a function of the angle theta, alongside conservation of mechanical energy equations. By manipulating these equations, a relationship such as sin θ = constant or cos θ = constant can be derived. The solution ultimately reveals that the particle leaves the sphere at a distance of b/3. The problem, while seemingly complex, can be solved with systematic mathematical approaches.
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Homework Statement



A Particle is place on a smooth sphere of radius b at a distance b/2 above the central plane. As the particle slides down the side of the sphere at what point will it leave?

Homework Equations



potential and kinetic energies

The Attempt at a Solution



no idea
 
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The particle leaves the sphere when the normal force is zero. So the only force acting on it will be the gravitational force.

Find the centripetal component of the gravitational force as a function of the angle theta. Then write the expressions for the conservation of mechanical energy, and use the fact that F = (mv^2)/b. A few mathematical manipulations later, you will find an expression of the type sin θ = constant, or cos θ = constant. Use the arc sine or arc cosine functions accordingly to find θ. That will be your answer. You may transform to rectangular coordinates if the problem asks for it.

I know it sounds like a lot of work, but it actually isn't.
 
Thanks, i actually managed it, it came b/3 :)

Thanks for the help.
 
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