- #1

quicksilver123

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## Homework Statement

see attachment for question wording.

a) find acceleration

b) find horizontal displacement

c) find final velocity

v

_{x}=4.0*10^6m/s

ε=4.0*10^2 N/C

Δd

_{y}=0.02m

mass of electron = m

_{e}= 9.11*10^-31kg

charge of electron = q

_{e}= -1.6*10^-19 C

## Homework Equations

suvat

electric field equation

coulombs laws

## The Attempt at a Solution

a)

ma=qε

(9.11*10^-31)(a)=(1.6*10^-19)(4*10^2)

acceleration = 7.025246981*10^13 m/s/s [down]

b)

Δd

_{y}=v

_{i y}Δt+0.5(a

_{y})Δt^2

Δt = 2.4*10^-8 seconds

Δd

_{x}= vΔt

Δd

_{x}= (4*10^6)*2.4*10^-8)

Δd

_{x}= 0.096m

Δd

_{x}= 9.6cm

c)

v

_{f y}^2 = v

_{i y}^2 +2a

_{y}Δd

_{y}

v

_{f y}= √(0+1.34884742*10^13)

v

_{f y}= 3.672665817*10^6 m/s

I'm pretty confident in parts A and B but I'm not sure about part C.

I still have to find the direction of the final velocity; waiting to see if the magnitude is correct first.

#### Attachments

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