Particle moving with radial velocity

AI Thread Summary
A particle moves with a constant radial velocity of 4 m/s and a constant angular velocity of 2 rad/s when it is 3 m from the origin. The tangential component of velocity is calculated as 6 m/s using the formula v = ω × r. The total velocity is found by vector addition of the radial and tangential components, resulting in a magnitude of √(4² + 6²) = √52 m/s. To find acceleration, the discussion suggests using polar coordinate equations, although radial and angular accelerations are zero in this case. The conversation emphasizes the importance of understanding vector components in calculating velocity and acceleration.
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Homework Statement


A particle moves in a plane with constant radial r=4m/s. The angular velocity is constant and has magnitude \Theta=2rad/s. When the particle is 3m from the origin, find the magnitude of the velocity and the acceleration.


Homework Equations





The Attempt at a Solution


The answer is v=root of 52 m/s. But I don't know how to get this number. Can somebody give me a hint?
 
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Radial velocity is constant at 4m/s.So when its 3m from origin,the tangential component of velocity is given by v=omega X r, ie 6m/s in this case
Now you have the mutually perpendicular radial and tangential components as 4m/s and 6m/s,calculate the final velocity by vector addition.
 
As an alternative to calculate speed and acceleration in Cartesian coordinates you may also want to find inspiration in the normal polar equations for velocity and acceleration, see for instance [1]. These equations are more general as they also allow for radial and angular accelerations, but in your case those are zero and inserting that you end up with two simple vector equations to take magnitude of.

[1] http://en.wikipedia.org/wiki/Polar_coordinate_system#Vector_calculus
 
Can I find acceleration by a=v\Theta/(1-cos\Thetat)?
 
Can somebody answer me?
 
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