I Particle Physics and Quantum Mechanics

crastinus
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I’m having a hard time, as I begin learning QM, knowing what it applies to, if I can put it that way.

Is QM the rules that describe how the particles of the Standard Model interact with each other? Or what is the best way to understand the relationship between what one studies when one studies QM and what one studies when one studies the standard model?
 
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Quantum mechanics is necessary for understanding the Standard Model, but it's also possible to form many other theories in QM in addition to SM. This is similar to how Newton's first, second and third laws are necessary for understanding the classical theory of gravity, but can be applied to other things, too.
 
crastinus said:
I’m having a hard time, as I begin learning QM, knowing what it applies to, if I can put it that way.

Our modern electronics, such as your microprocessor, your mobile devices, your computers, etc.. are all built on QM.

Modern medicine, such as MRI, are built on QM.

QM's applications are all around you. You do not have to reach out as far as the Standard Model or particle physics to find them.

Zz.
 
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Believe it or not classical mechanics is built on QM. But first you need to learn QM to the level of path integrals and Classical Mechanics at the level of a book like Landau - Mechanics.

Thanks
Bill
 
Thanks for the help!
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
Not an expert in QM. AFAIK, Schrödinger's equation is quite different from the classical wave equation. The former is an equation for the dynamics of the state of a (quantum?) system, the latter is an equation for the dynamics of a (classical) degree of freedom. As a matter of fact, Schrödinger's equation is first order in time derivatives, while the classical wave equation is second order. But, AFAIK, Schrödinger's equation is a wave equation; only its interpretation makes it non-classical...
Thread 'Lesser Green's function'
The lesser Green's function is defined as: $$G^{<}(t,t')=i\langle C_{\nu}^{\dagger}(t')C_{\nu}(t)\rangle=i\bra{n}C_{\nu}^{\dagger}(t')C_{\nu}(t)\ket{n}$$ where ##\ket{n}## is the many particle ground state. $$G^{<}(t,t')=i\bra{n}e^{iHt'}C_{\nu}^{\dagger}(0)e^{-iHt'}e^{iHt}C_{\nu}(0)e^{-iHt}\ket{n}$$ First consider the case t <t' Define, $$\ket{\alpha}=e^{-iH(t'-t)}C_{\nu}(0)e^{-iHt}\ket{n}$$ $$\ket{\beta}=C_{\nu}(0)e^{-iHt'}\ket{n}$$ $$G^{<}(t,t')=i\bra{\beta}\ket{\alpha}$$ ##\ket{\alpha}##...

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