Passengers apparent weight on elevator when it's acceleration is negative

AI Thread Summary
The discussion focuses on calculating a passenger's apparent weight in an elevator under different acceleration conditions. For zero acceleration, the passenger's weight is calculated as 735 N using the formula w=mg. When the elevator accelerates positively, the apparent weight increases, while a negative acceleration results in a decrease in apparent weight. The key equations provided are apparent weight = w*(1 + a/g) for positive acceleration and apparent weight = w*(1 - a/g) for negative acceleration. The problem emphasizes understanding the relationship between acceleration and apparent weight rather than finding specific numerical values for parts b and c.
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Homework Statement


There's a 75 kg passenger in an elevator
a. what is the passenger's apparent weight when acceleration is zero?
b. what is the passengers apparent weight when acceleration is positive?
c. what is the passengers apparent weight when acceleration is negative?


Homework Equations


w=mg
apparent weight=w*(1 + a/g)
apparent weight =w*(1 -a/g)


The Attempt at a Solution



a. w=75kg*9.8m/s=735N

b. apparent weight=735*(1 + a/g)

a=F/m I'm not sure how to find F here?

c.

 
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His WEIGHT is 75 kg so that's including gravity ;)
 
Part a is correct. You have the correct equations for parts b and c, (although by using w=mg, the equation is simplified). The problem, as written, is not looking for a numerical solution to parts b and c. For parts b and c, is the apparent weight greter than, less than , or equal to, a certain value?
 
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