MHB Pb.20 What is the probability that Hiroko....will be chosen

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The discussion revolves around calculating the probability of Hiroko being chosen as the representative from a 35-member History Club, excluding 3 officers. The correct probability is determined to be 1/32, as there are 32 eligible members after excluding the officers. Participants emphasize that there is no single "approved" method for solving such problems, highlighting the importance of logical reasoning. The conversation also touches on the desire for more complexity in the problem and the sharing of different perspectives for learning. Overall, the focus remains on understanding probability through logical deduction rather than formal methods.
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The 35 member History Club is meeting to choose a student government representative. \item The members decide that the representative, who will be chosen at random, CANNOT be any of the 3 officers of the club.
What is the probability that Hiroko, who is a member of the club but NOT an officer, will be chosen?

a. $0 \quad$ b. $\dfrac{4}{35} \quad$ c. $\dfrac{1}{35} \quad$ d. $\quad {\dfrac{1}{3}}\quad$ e. $\dfrac{1}{32}$
I chose e
ok, I don't know the approved and official method to solve this
just subtracted 3 from 35 and that was the probability

I'm going to study (on my own, not in a class) probability and statistics for february march and april
so I will be posting a lot here
 
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First, no matter what your teachers tell you, there is NO "approved and official method" of solving a problem. As long as you get the right answer and know that you have the right answer, that's sufficient! Logical thinking gives you that.

Second, since the three officers of the club are not eligible to serve, there are 35- 3= 32 who are. That is the logical thinking you were doing, perhaps without realizing it. That is the reason you subtracted 3, for three officers who are not allowed to serve. The next step is two realize that, since all of the remaining 32 people are "equally likely" to be selected, and probabilities must add to 1, each must have probability 1/32.

Finally, stop bragging about living in Hawaii and surfing in January!
 
actually i have never surfed in Hawaii
even though i live just a short drive from the famous pipeline

Anyway
 
Hi karush!

Part of me wants this problem to be more complicated than it seems, but I agree with you that it should be (e). There are 32 valid options to choose from at random, so 1/32 of a single person being chosen from that pool.
 
well sometimes i post a problem,,, even though i know how to solve it just to get more view points
lots of little unknown tricks and tips out there..

yeah I am not in a class room so there is no father figure..
 
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