Peak electric field of a laser light.

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SUMMARY

The discussion focuses on calculating the peak electric field of a laser light with an average power of 7.0 W and a beam diameter of 1.0 mm. The average intensity was correctly calculated as 8,912,676 W/m² using the formula Intensity = P/A, where A is the area of the beam. The user seeks assistance in determining the peak electric field, which is directly related to the intensity of the light. The relationship between electric field and intensity is crucial for solving part B of the problem.

PREREQUISITES
  • Understanding of laser physics and average power calculations
  • Familiarity with the formula for intensity (Intensity = P/A)
  • Knowledge of the relationship between electric field and intensity
  • Basic geometry for calculating the area of a circle
NEXT STEPS
  • Research the formula for peak electric field in relation to intensity (E = √(2 * I / ε₀))
  • Study the concept of electromagnetic waves and their properties
  • Learn about the significance of laser beam diameter in intensity calculations
  • Explore practical applications of peak electric field in laser technology
USEFUL FOR

Students in physics, particularly those studying optics and electromagnetism, as well as professionals working with laser technologies and applications.

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Homework Statement




A laser produces an average power of 7.0 W in a light beam 1.0 mm in diameter. Find (a) the average intensity and (b) the peak electric field of the laser light


Homework Equations



Intensity = P/ A
Unsure about part B

The Attempt at a Solution



For part A I did P/( ∏ * r^2) which came to be 7W/( ∏ * .0005^2) which came to 8912676 w/m^2

But I need help finding out how to do part B. Any help would be great.
 
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