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## Homework Statement

A 400 loop circular armature coil with a diameter of 5cm rotates at 60rev/s in a uniform magnetic field of strength 1T.

a) What is the peak voltage output of the generator?

b) What is the RMS voltage output of the generator?

## The Attempt at a Solution

a) My answer seems a tad large, I think I'm doing something wrong but can't quite pick it...:yuck:

ε=NBAωsin(ωt)

ε=400*1*(pi*2.5²)*(60*2pi)*1

ε=2960881V

b) RMS=ε*[1/√(2)]

(Leaving it for now as it depends on the answer from part a)