Peak voltage output of a generator

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Homework Statement


A 400 loop circular armature coil with a diameter of 5cm rotates at 60rev/s in a uniform magnetic field of strength 1T.

a) What is the peak voltage output of the generator?
b) What is the RMS voltage output of the generator?

The Attempt at a Solution



a) My answer seems a tad large, I think I'm doing something wrong but can't quite pick it...
ε=NBAωsin(ωt)
ε=400*1*(pi*2.5²)*(60*2pi)*1
ε=2960881V

b) RMS=ε*[1/√(2)]
(Leaving it for now as it depends on the answer from part a)
 
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Convert 5cm to 0.05m. Reduces answer by a factor of 10000.
 
apelling said:
Convert 5cm to 0.05m. Reduces answer by a factor of 10000.

Silly me...
 
why is sin(wt) = 1?

is it because its a dc generator?