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Simple Generator - Calculating N Loops

  1. Sep 26, 2012 #1
    Simple Generator - Calculating "N" Loops

    1. The problem statement, all variables and given/known data

    A simple generator is used to generate a peak output voltage of 26.0 V . The square armature consists of windings that are 6.3 cm on a side and rotates in a field of 0.440T at a rate of 60.0 rev/s. How many loops of wire should be wound on the square armature?
    Express your answer as an integer.

    2. Relevant equations

    ε / 2Blv sin θ = N

    3. The attempt at a solution

    l = 0.063 m
    ε = 26.0 V
    B = 0.440 T
    v = 1.89 m/s (Is this what is incorrect?)

    v = ωr
    v = (60.0 rev/s)(0.0315 m)
    v = 1.89 m/s

    (26.0 V) / (2)(0.440 T)(0.063 m)(1.89 m/s)

    (26.0 V) / (.104 T m^2 / s) = 250 loops

    ETA : I assumed the angle is 90 degrees.
     
  2. jcsd
  3. Sep 26, 2012 #2

    ehild

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    Gold Member

    Re: Simple Generator - Calculating "N" Loops

    ω=2pi times revolutions/second

    ehild
     
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