Lievo said:
I don't think either, but wouldn't be the smart move to do?
Sure, they need to show more before one spend weeks on that. However, did your quick look reveals that any of these 10 plots that includes 1 maybe-concentric-thing also includes several?
You know, I see why one may expect to see something like that even in random reconstruction, but I don't see why one should expect to always see several when there is at least one. Or do you see a reason?
Don't really see a reason, no.
Basically, I think it just comes down to the physics of the CMB. The most simple model for the CMB is that you have a bunch of waves on the sky, and each wave draws its amplitude from a random Gaussian distribution that only depends upon the wavelength.
In mathematical terms, it's the statement that:
P(a_{\ell m}) \propto e^{-a_{\ell m}a^*_{\ell m} \over 2C_\ell}So here's the question: if I have a random distribution where the variables are independent in harmonic space, what does that mean for real space?
Well, as long as C_\ell is non-constant, the real space distribution will also be Gaussian, but highly correlated. The covariance matrix becomes:
\sum_\ell {2\ell + 1 \over 4\pi} C_\ell P_\ell(\cos \theta_{ij})
Here P_\ell(\cos \theta) are the Legendre polynomials. I'm not sure it would be useful to go into detail about what these are, but the most important consideration is this: the entire covariance matrix is just a function of \theta_{ij}. What is this parameter?
This is the angle across the sky between pixel i and pixel j.
This means that different pixels on the sky are very highly correlated, and they are correlated by an amount that depends upon the angle of separation between them. Fundamentally this means that when you're binning up the pixels on the sky, the number of degrees of freedom is much smaller than the number of pixels in the bins. So with fewer random variables to average things out, you expect much larger variations from the expectation based just upon the number of pixels and assuming those pixels are independent.
Furthermore, by looking specifically at circles on the sky, which are a constant angle from some central point, you're exacerbating the visibility of any effect here because all pixels in each ring will have the same amount of correlation with the central pixel.