Percentage saving in weight of sloid shaft Vs hollow shaft

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SUMMARY

The discussion focuses on calculating the percentage saving in weight when replacing a solid shaft with a hollow shaft, where the internal diameter of the hollow shaft is 60% of its external diameter. The length, material, and maximum shear stress remain constant. Key equations involve calculating the volume of both shaft types using the formula for volume based on cross-sectional area and height. The participants emphasize the importance of maintaining applied torque and shear stress while determining the cross-sectional area reduction.

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  • Understanding of solid and hollow shaft mechanics
  • Familiarity with volume calculations for cylindrical objects
  • Knowledge of shear stress principles
  • Basic algebra for manipulating equations
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I have calculated the external diameter and the solid shaft is to be replaced by a hollow shaft whose internal diameter equals 60% of the external diameter, the length, material, and maximum shear stress remaining unchanged.

How can I calculate the percentage saving in weight?
What are the equations that are relative to this?

Thank u for ur help
 
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adam333 said:
I have calculated the external diameter and the solid shaft is to be replaced by a hollow shaft whose internal diameter equals 60% of the external diameter, the length, material, and maximum shear stress remaining unchanged.

How can I calculate the percentage saving in weight?
What are the equations that are relative to this?

Thank u for ur help

Hi adam333! Welcome to PF! :smile:

Hint: volume = cross-section-area times height …

so how much is the cross-section-area reduced? :wink:
 
adam333: For the hollow versus solid shaft, hold applied torque and maximum shear stress constant, and set inside diameter of the hollow shaft equal to 60 % of the outside diameter of the hollow shaft. List relevant equations, and show your work.
 

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