Perpendicular Graphs: Finding A1/B1 Using Negative Reciprocal | Homework Help

AI Thread Summary
When two lines represented by the equations A1x + B1y = C1 and A2x + B2y = C2 are perpendicular, the slopes are negative reciprocals of each other. The correct expression for A1/B1 in terms of A2 and B2 is -B2/A2. There is confusion regarding the correctness of this expression, with some users feeling that it should not be marked incorrect. The discussion highlights frustrations with online homework systems misgrading correct answers. Understanding the relationship between the coefficients is crucial for solving problems involving perpendicular lines.
eXmag
Messages
36
Reaction score
0

Homework Statement



If the graphs of A1x + B1y = C1 and A2x + B2y = C2 are perpendicular, express the following in terms of A2 and B2.

A1/B1= ?

Homework Equations



Negative reciprocal


The Attempt at a Solution



I thought that by expressing A2 and B2 with A1/B1, it would just be the negative reciprocal if its perpendicular so it would be -B2/A2 which is incorrect.
 
Physics news on Phys.org
eXmag said:

Homework Statement



If the graphs of A1x + B1y = C1 and A2x + B2y = C2 are perpendicular, express the following in terms of A2 and B2.

A1/B1= ?

Homework Equations



Negative reciprocal


The Attempt at a Solution



I thought that by expressing A2 and B2 with A1/B1, it would just be the negative reciprocal if its perpendicular so it would be -B2/A2 which is incorrect.

It shouldn't be marked as incorrect. It looks correct to me.
 
This is how webassign screws you over!
 
Thanks for the response! I knew it was correct
 
Back
Top