(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

perpendicular

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a)Find the eqution of the plane that contains points (2,-1,4) , (3,2,-1)

and perpendicular to the plane x+y+2z=3

b)Find the equation of the plane containing the point (3,-1,-5) and perpendicular to the planes 3x-2y+2z = -7 and 5x-4y+3z=-1

2. Relevant equations

The vector normal to the plane is (1,1,2). You know it from the coefficients in front of x,y and z.

i know that this vector will be part of the perpendicular plane since it is the normal vector. Then i want the vector linking points (2,-1,4) , (3,2,-1) to be in the perpendicular plane as well.

how to Find this vector and compute the cross product with the normal vector (1,1,2). This will give you the normal vector of the perpendicular plane (say (a,b,c)).

3. The attempt at a solution

as above in b

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# Homework Help: Perpendicular plane equation help

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