PH of weak acid/weak base salts

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The discussion centers on demonstrating that calcium carbonate (CaCO3) is basic, contrasting the behavior of calcium ions (Ca^2+) from calcium hydroxide (Ca(OH)2) and carbonate ions (CO3^2-) from bicarbonate (HCO3^-). It is noted that the reaction involving Ca^2+ and water produces H3O^+, which is incorrectly framed as it suggests acidity, while the carbonate reaction produces OH^-, indicating basicity. The solubility of Ca(OH)2 is low, leading to the conclusion that Ca^2+ acts as a spectator ion, and the equilibrium for the carbonate reaction shows a significantly larger K value, affirming its basic nature. The final pH of a saturated CaCO3 solution is calculated to be around 9.73, emphasizing its basic properties. Overall, the discussion highlights the importance of understanding the equilibrium and solubility dynamics of these compounds in demonstrating the basicity of CaCO3.
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I'm trying to show my students that CaCO_3 is basic.
Ca^2^+ comes from Ca(OH)_2, which is a weak base due to it's low solubility. CO_3^2^- comes from the weak acid HCO_3^-. To compare the two we compare:

1) Ca^2^+ + H_2O --> Ca(OH)_2 + H_3O^+

and

2) CO_3^2^- + H_2O --> HCO_3^- + OH^-

We want to compare the K values. It is clear that equation 2 will have a significantly larger K value and the solution will be basic, but where can a person find a K value for something like equation 1?
Are there charts for the Ka of metal ions?
What order of magnitude is it? I imagine Ka for 1 is <<< Kw
 
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I don't think equation 1 will occur appreciably, calcium hydroxide is fairly soluble in water so you can reasonably neglect it; thus calcium is a spectator ion (solubility of calcium hydroxide is .18g/100mL).
 
The first reaction isn't even correct and frankly I don't know why you think that a strong base like calciumhydroxide would create an acidic particle like H3O^+.

This reaction would occur:
Ca(H_2O)_6^{2+}(aq)+H_2O(l) \rightleftharpoons CaOH(H_2O)_5^+(aq)+H_3O^+(aq) Which explains why a solution of CaCl_2 is acidic.

The second reaction is also incorrect since it's an equilibrium:
CO_3^{2-}(aq) + H_2O(l) \rightleftharpoons HCO_3^-(aq) + OH^-(aq)
 
Ca(OH)_2
pKb1 = 2.43
pKb2 = 1.40
(http://ifs.massey.ac.nz/resources/chemistry/dissociation/inorgbases.htm )

H_2CO_3
pKa1 = 6.37
pKa2 = 10.25

CaCO_3
pKso = 8.3

So the concentration of saturated CaCO_3 solution is 7.1\cdot10^{-5}

pH calculated using BATE is 9.73.

(see http://www.chembuddy.com/?left=pH-calculation&right=pH-salt-solution for general approach to pH calculation of salt solution).

In fact final pH will be different, as you should take into account increased solubility of CaCO_3 (due to Ca^{2+} and CO_3^{2-} hydrolysis - although the first can be neglected, as Ca^{2+} is dominant at 99.9% of total calcium concentration).
 
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