Phase Power Calculation: Determining Total Power Input into System

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
TurboST2
Messages
3
Reaction score
0

Homework Statement


I need to calculate the power for phase A, B, and C so that I can determine the total power into the system.

I have measured the following data:
VA magnitude = 117.7 [v]
VA angle = 0°
IA magnitude = 7.5 [A]
IA angle = -25.5°
VB magnitude = 117.7 [v]
VB angle = -124.1°
IB magnitude = 7.7 [A]
IB angle = -145.7°
VC magnitude = 117.2 [v]
VC angle = 117.5°
IC magnitude = 7.3 [A]
IC angle = 94.8°

Homework Equations


P=IV

The Attempt at a Solution


Does this mean?:
Phase A power = 882.75 [w]
Phase B power = 906.29 [w]
Phase C power = 855.56 [w]

Total power into system = 2644.6 [w]
 
Physics news on Phys.org
Hi TurboST2 :welcome:

So you didn't take phase angle into account? That means you've calculated volt-amps for each phase, not watts.

Does your textbook show a formula for AC power?
 
Thank you for the helpful reply. No I did not take the phase angle into account. I wasn't sure if this was necessary for calculating power in this way.

Taking the angle into account would I use this equation instead? P=VIcos(θv-θi) giving the following results:

Pa = 796.75 [w]
Pb = 842.64 [w]
Pc = 789.28 [w]

Ptotal = 2428.67 [w]
 
If you showed the data you used in arriving at those new numbers, it would be easy to judge whether you are on the right track.

What is the nature of your load here?