Phonon density of states and density of states of free electrons

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The discussion focuses on calculating the density of states (DOS) for free electrons and phonons. The free electron DOS is found to be proportional to energy^(-1/2) in 1D and constant in 2D. There is uncertainty regarding the phonon DOS, specifically whether it should be expressed in terms of energy D(E) or frequency D(ω). It is suggested that phonon DOS can be related to energy through the dispersion relation, resembling that of photons. Resources like Kittel and Ashcroft and Mermin are recommended for further understanding of phonon DOS calculations.
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Homework Statement
Compare phonon DOS and DOS of free electrons in 1D and 2D
Relevant Equations
D(E)1d=(1/L)dN/dE
D(E)2d=1/A)dN/dE for electrons
In the following pdf I tried to calculate the density of states of free electrons and phonons. First, I found the free electron DOS in 1D, it turns to be proportional to (energy)^(-1/2) and in 2D it is constant. However, I am not sure I found the DOS for phonons in the second part of the solution. Because the homework said to compare two DOS, I thought phonon DOS needs to be in terms of energy D(E) and not frequency w D(w). But I suspect it is wrong. Can phonon density of states be in terms of energy? If so, how to find it? And if not, should I find it trough equation D(w)dw?
 

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This is a pretty broad question and I would suggest looking at Kittel or Ashcroft and Mermin for the phonon part. I believe the question wants you to see that the dispersion relation for phonons can resemble that of photons. There is a lot of good physics in this question and it is worth some effort.
 
I`ve looked up the DOS of a phonon in Kittel`s book and in 1D DOS is 1/pi*vg (vg as a group velocity dw/dk) and in 2D it`s k/2pivg . Both of them have no relationship with energy. That is why I was wondering if there is a way to calculate the DOS as a function of energy.
 
$$E=\hbar \omega$$
 
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