Understanding the Energy Transfer of Phonons in Acoustic Particles

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SUMMARY

This discussion centers on the nature of phonons, which are defined as the normal modes of lattice vibrations in solids, distinct from sound waves in gases. Phonons represent discrete packets of energy, and their behavior is characterized by their propagation through solid materials, unlike photons that can travel through vacuums. When sound fades, the energy associated with phonons dissipates in a stepwise manner, correlating with the amplitude of the vibrations in the solid. The conversation highlights the importance of understanding phonons as units of energy rather than merely vibrations.

PREREQUISITES
  • Understanding of solid-state physics concepts
  • Familiarity with wave-particle duality
  • Basic knowledge of energy quantization
  • Awareness of lattice dynamics in materials
NEXT STEPS
  • Research "phonon dispersion relations" in solid-state physics
  • Explore "acoustic vs. optical phonons" and their properties
  • Learn about "energy quantization in solids" and its implications
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Physicists, materials scientists, and students studying solid-state physics or acoustics will benefit from this discussion, particularly those interested in the energy transfer mechanisms in solids.

motai
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Is there any general information that I can get about these discrete acoustical particles? I know that they have the same wave-like properties as photons, but they also have quite a few differences (i.e. sound by itself diminishes over time and does not exist in places with lack of a medium such as air).

What I am curious about is the energy related to phonons. What happens to the phonons when sound fades? Suppose I am playing an instrument, the air I supply to it causes the air to vibrate in the instrument, thus providing sound. Where does the energy transfer to?Does the wavefunction of the phonon gradually fade from, let's say sin[x] to 0?
 
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Originally posted by motai
Is there any general information that I can get about these discrete acoustical particles? I know that they have the same wave-like properties as photons, but they also have quite a few differences (i.e. sound by itself diminishes over time and does not exist in places with lack of a medium such as air).

What I am curious about is the energy related to phonons. What happens to the phonons when sound fades? Suppose I am playing an instrument, the air I supply to it causes the air to vibrate in the instrument, thus providing sound. Where does the energy transfer to?Does the wavefunction of the phonon gradually fade from, let's say sin[x] to 0?

Somehow, based on your question, I have the impression that you are associating phonons with sound vibrations in AIR. Phonons are not well-defined in air (or gasses for that matter). Rather, phonons are the normal modes of lattice vibrations in SOLIDS. It is one of the more common form of "elementary excitation" of solids. It exists due to the lattice ion vibrations and requires a nearest-neighbor, next-nearest neighbor, etc. interactions, which one doesn't have in a typical gas state. Not only that, there are acoustic and optical phonons that occur depending on how those ions are displaced relative to one another during the normal modes vibrations.

An elementary explanation of what phonons are can be found at the Hyperphysics site (which is a good resource to start with when one has any basic physics question) at

http://hyperphysics.phy-astr.gsu.edu/hbase/solids/phonon.html

Zz.
 
Originally posted by motai
I know that they have the same wave-like properties as photons, but they also have quite a few differences ...
What wave-like properties do they have that are the same?




Originally posted by motai
What I am curious about is the energy related to phonons.
They are energy; discrete "packets" of it. A lattice can only gain or lose sonic energy in the amount of these packets.




Originally posted by motai
Does the wavefunction of the phonon gradually fade from, let's say sin[x] to 0?
What is the "wavefunction of the phonon?" A phonon is an amount of energy. Imagine a crystal is vibrating at a certain amplitude at a pure frequency. If this vibration decays (emitting sound into the air), it will do so in a stepwise fashion. Each step down in amplitude is the loss of a phonon. Of course, these steps are extremely small, because the frequency is sonic.
 
Ah, I see. So phonons are just energy vibrations that propagate through the bonds in the solids. And since phonons are not well-defined in air, they disspiate compared to photons (which not only can travel through a gaseous medium but also through a vacuum). I get it now. Thanks for the help ZapperZ and turin.
 
Originally posted by motai
Ah, I see. So phonons are just energy vibrations that propagate through the bonds in the solids. And since phonons are not well-defined in air, they disspiate compared to photons (which not only can travel through a gaseous medium but also through a vacuum). I get it now. Thanks for the help ZapperZ and turin.
I'm afraid that you still might have a slight misconception. Think of a phonon as a unit of energy, like a Joule or an eV (only a phonon is much smaller than even an eV). It is not quite this simple, but I think it will give you a better picture than referring to a phonon as an "energy vibration that propagates." Saying this would be like saying an eV is a vibration that propagates. Though, if saying this about an eV makes sense to you, then I may just be arguing semantics, and for that I would appologize.
 
Originally posted by turin
I'm afraid that you still might have a slight misconception. Think of a phonon as a unit of energy, like a Joule or an eV (only a phonon is much smaller than even an eV). It is not quite this simple, but I think it will give you a better picture than referring to a phonon as an "energy vibration that propagates." Saying this would be like saying an eV is a vibration that propagates. Though, if saying this about an eV makes sense to you, then I may just be arguing semantics, and for that I would appologize.

I never thought about it as a unit, but it makes sense.

No need to apologize, this is a pretty new concept to me. Its more complex than I thought it would originally be. But its a learning process, and I appreciate your help.
 

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