charters said:
Is this a Reeh Schlieder argument, ie the asymptotic detector is compactly supported but the asymptotic N particle states are global, and these don't commute? Or are you saying something else here?
Basically that. It's a corollary of the Reeh-Schlieder theorem.
charters said:
though I am unsure if this still holds in string theory, so perhaps this is a symptom of underlying pathologies in QFT and should not be trusted
I don't think we should not trust a feature of a stringently tested physical theory (QFT) because it's not present in a incompletely developed theory with no experimental support (String Theory).
charters said:
then it does appear to follow a superposition of paths through spacetime. There does seem to be a wavepacket that traverses the intervening spacetime between detectors
This is going into interpretation stuff, about the quantum state being a "real" wave.
Ignoring this, even for two photons we don't have this notion of a wavepacket traversing intervening spacetime since it isn't a function on spacetime.
The point is in QED particulate behavior only manifests in specific detector types at asymptotic times. If you'd used the wrong types of detectors you don't get particle behavior even at asymptotic times. Really this is because QFT promotes "particle" to having the same counterfactual difficulties that spin and other observables have in non-relativistic QM.
charters said:
source to detector with no presence along a path in the meantime
Even in fixed particle QM though talking about "paths in the meantime" is fraught with difficulty.
The thread is originally about photons, but my comments are more about particles in general in QFT. In QFT both electrons and photons are associated with asymptotic detectors, which due to Reeh-Schlieder are necessarily always noisy, i.e. no state definitely causes ##N## clicks.
The noise in a detector is related to its size, i.e. the standard deviation of clicks is proportional to the detector volume. However for electrons since they are massive the standard deviation decays as ##\mathcal{O}\left(e^{-mV}\right)## and for photons it is only something like ##\mathcal{O}\left(\frac{1}{V^{a}}\right)## for some ##a##.
Ultimately this is related to photons not really having a non-relativistic limit. Since position operators of particles aren't really a "native" notion to QFT, being able to construct one is in essence asking if you can form a well-defined single particle non-relativistic quantum theory. For electrons you can, since errors in detectors fall off exponentially and they have a non-relativistic limit. Photons don't satisfy either of these so you can't.