Photon emission during x-Ray ionization process

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SUMMARY

The discussion centers on photon emission during the x-ray ionization process, specifically addressing the confusion surrounding the energy dynamics involved. Marco Uscanga raises a question about how expelled electrons can take all the radiant energy, leaving no excited states for photon emission. Participants clarify that while ionization occurs when an x-ray collides with an atom, resulting in electron expulsion, quantum mechanics allows for the probability of photon emission during such collisions. The conversation highlights the complexities of particle interactions and the various outcomes based on energy levels and particle types.

PREREQUISITES
  • Understanding of x-ray ionization processes
  • Basic principles of quantum mechanics
  • Knowledge of photon emission and energy conservation
  • Familiarity with particle physics concepts
NEXT STEPS
  • Study the principles of x-ray ionization in detail
  • Explore quantum mechanics, focusing on photon emission probabilities
  • Research particle collision outcomes in high-energy physics
  • Investigate the conditions for electron-positron pair production
USEFUL FOR

Physicists, students of quantum mechanics, and anyone interested in the interactions of x-rays with matter will benefit from this discussion.

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Dear mates:

During ionization with radiant energy there is a photon emission (see http://hyperphysics.phy-astr.gsu.edu/hbase/mod3.html). I know photon emission occurs by a decay of radiant energy from a excited state and what is confusing to me (I can't find a logical conection) is that the expulsed electron from ionization takes all the radiant energy and leaves the atom without excited levels for energy decayment.

Waiting for comments

Marco Uscanga
 
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I'm not sure what you find confusing. An x-ray is colliding with an atom and -- because it has so much energy compared to the electric potential energy that holds the electron to the nucleus -- it knocks off the electron (ionizes it). Quantum mechanics tells you that there is also a probability that a photon is emitted as a result of this collision, which would carry off some of the momentum/energy. If you repeat the experiment over and over, some of the time you will get no photon, and sometimes you will get a photon...
You don't necessarily have to have excited bound electrons in order to create a photon... I don't know where you got this notion. Photon(s) can result from a particle collision directly (like a meson hitting a proton for example).
 
ok Euquila! I think I have to take into account that Quantum mechanics tells you that there is also a probability that a photon is emitted as a result of this collision, which would carry off some of the momentum/energy
 
Ya quantum mechanics is very interesting. For example, it is also possible that in this collision that a electron-positron pair is created, provided that the x-ray has enough energy with respect to the sum of the rest masses of these 2 daughter particles E_photon >= 2*m_e, with c=1. What you should realize is that when 2 particles collide, there are many outcomes that can occur with various (or even equal) probabilities depending on the which particles are colliding (gluons, photons, protons, etc...), their energies and momenta, whether they have integer spin (boson) or fractional spin (fermion), and other properties too...
 

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