Physical and analytical chemistry

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SUMMARY

The solubility of solid substance X in water at 20 degrees Celsius is 42g/L. Three solutions are analyzed: S1 at 5.1g/L, S2 at 39g/L, and S3 at 57g/L. To saturate S1, it is confirmed that combining equal volumes of S1 and S2 does not yield a concentration above 42g/L; therefore, S3 must be used to achieve saturation. The principle that dilute solutions cannot be mixed to create a more concentrated solution is established as a key fact.

PREREQUISITES
  • Understanding of solubility concepts
  • Knowledge of solution concentration calculations
  • Familiarity with the principles of mixing solutions
  • Basic grasp of physical chemistry terminology
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  • Study the principles of solution concentration and dilution
  • Learn about saturation and supersaturation in solutions
  • Explore the concept of colligative properties in physical chemistry
  • Investigate the role of temperature in solubility
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Chemistry students, physical chemists, and laboratory technicians involved in solution preparation and analysis.

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at 20 degree celsius, the solubility of a solid substance x in water is 42g/L. There are 3 solutions containing x kept at this temperature: S1 5.1g/L, S2 contains 39g/L, and S3 contains 57g/L.

if we want to make S1 saturated with x, is it possible that we can add an equal volume of S2 and S1 because the overall concentration will become about 44g/L. or is it we must add more S2? what equation should I use?
 
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The answer is no. You cannot combine dilute solutions in any proportion to get a more concentrated one. You must use S3.
 

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