alxm said:
Yes. Psi in (2) is defined as being what it is in (1). These are not two separate definitions of the wave function.
That's exactly what they do. To within experimental accuracy, which is something like 10-12 digits in the case of hydrogen. There are few physical phenomena which are as theoretically well-verified as the quantum mechanics of the hydrogen atom.
You mean the probability density and the energy calculation based on the wavefunction are
inseparable ?
As you know, in the energy calculation of the hydrogen atom, the Dirac equation is more correct than the Schrodinger equation.
But in the textbook, the probability density of the Dirac equation is
not written instead of the Schrodinger equation,
though the above two things are inseparable. Why?
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As shown in the two-slit or Davisson-Germer experiment, the electrons are moving obeying the
direction and the magnitude of the "momentum" expressed by its wavefunction, which means
this wavefunction is almost same as de Broglie's wave itself.
But in the wavefunction of the hydrogen atom, if the electrons are moving obeying the direction and the magnitude of the "momentum" expressed by its wavefunction at each point, its movement becomes "weird".
(For expample, if the momentum operator acting on the 1S (or 2P) hydrogen wavefunction means the "real"
direction and the magnitude of the electron's momentum at each point, the electron is
not oscillating (or rotating) around the nucleus, when
connecting each momentum vector.)
This means that the hydrogen wavefunction is
not de Broglie's wave itself though it uses the de Broglie's theory.
(So it is impossible that we consider the hydrogen wavefunction is "real wave" which is "compatible" with the de Broglie's theory.)
This is why the name "de Borglie's wave" is not used so much in QM ?
(As shown in the other threads, the "de Broglie's waves" and the "pilot waves" of de Broglie-Bohm theoy are
different things, aren't they?)