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brendan3eb
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Homework Statement
A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance d from the 50 cm mark. The period of oscillation is 2.5 s. Find d
Homework Equations
T=2PI*sqrt(I/mgh)
I(com)=(1/2)mL^2
parallel axis theorem
I=I(com)+m(L/2-d)^2
L=length of stick
h=L/2=center of mass
The Attempt at a Solution
so T=2.5 s
center of mass = .50 m
I=(1/2)mL^2 + m*(L/2-d)^2
then plug T, I, and h in for the equation
T=2PI*sqrt(I/mgh)
2.5 s=2PI*sqrt((3L^2/4-2Ld+d^2)/(gL/2))
however when I solve for d I do not get 5.6 cm..anyone see my mistake?