Physics help -- pushing a refrigerator across a wooden floor

[mememe1245]

I did attempt the problem, but I' now more confused than ever. Please help me.

Joe is moving his refrigerator to take to college and he begins by pushing it across
the wooden kitchen floor.

On a flat surface like the floor, how do you calculate how hard he needs to push?

Draw a free body diagram to help explain your answer and use the simulation Ramp:
Force and Motion to check your ideas.
1.Record the minimum force Joe would have
to use to move the refrigerator on the kitchen floor.

2. Later, Joe is ready to load his refrigerator onto the moving truck.

a. Explain how he would calculate how much force to use to lift the refrigerator straight
up into a truck.b. Joe starts thinking about easier ways to get it in the truck and remembers he has

some wood that he could use to make a ramp. How could he calculate the minimum

force needed to push it up the ramp?
-------------
Sorry I've been stuck on this for an hour :(

By using these...:
(kinetic/ sliding) mu=0.2
mass= 200kg
Normal Force= 2000N

 

[lightbender]

Do you know the refrigerator's mass?

 

[mememe1245]

200 kg

 

[lightbender]

So, first you would calculate the gravitational pull: G=gm, where g=9.8m/s

 

[mememe1245]

So, first you would calculate the gravitational pull: G=gm, where g=9.8m/s

G= 200kg * 9.8m/s^2 = 1960N?

 

[lightbender]

Oh, wait! I did not see that you changed your original thread!
Actually, first since the normal force is 2000N, the gravitational force is also 2000N.

 

[mememe1245]

Oh, wait! I did not see that you changed your original thread!
Actually, first since the normal force is 2000N, the gravitational force is also 2000N.

Okay...

 

[lightbender]

Then, to find the sliding friction force, you would do: Sliding=normal force x mu

 

[mememe1245]

Then, to find the sliding friction force, you would do: Sliding=normal force x mu

so, mu=force of friction/ force of Newton, right?

 

[lightbender]

mu is .2 from your original thread!

 

[mememe1245]

mu is .2 from your original thread!

Okay, I understand that mu = .2 and g= 2000N. What I don't understand is how to solve the problem.

 

[lightbender]

So, you just multiply them together resulting in the numerical value for sliding friction

 

[mememe1245]

So, you just multiply them together resulting in the numerical value for sliding friction

Ohhh...Waw! Thank u!

 

[lightbender]

The sliding friction answer is the equivalent to the minimum force needed to push the refrigerator! (answer in Newtons)
And Your Welcome!
Bye!

 

[mememe1245]

The sliding friction answer is the equivalent to the minimum force needed to push the refrigerator! (answer in Newtons)
And Your Welcome!
Bye!

Sorry...can I have more help with just two more questions? Please.