Physics Homework: A bead on wire

Click For Summary

Homework Help Overview

The problem involves a bead sliding on a wire in a vertical plane, influenced by gravity and friction. Participants are discussing the effects of these forces on the bead's velocity and kinetic energy at various points along the wire.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are analyzing the relationship between velocity and kinetic energy at different points, questioning the effects of friction and gravity. They discuss whether the bead's speed remains constant or changes due to these factors.

Discussion Status

Some participants have provided feedback on the original poster's attempts, suggesting reconsideration of certain statements, particularly regarding the presence of friction and its impact on speed and energy. There is an ongoing exploration of the implications of these forces.

Contextual Notes

There are constraints related to the visibility of the problem statements due to image loading issues, which may affect the clarity of the discussion. Participants are also encouraged to provide textual representations of the problems for better understanding.

Elliott98
Messages
3
Reaction score
0

Homework Statement


A bead slides on a wire, which is in a vertical plane, as shown in the diagram. Gravity acts in the -y direction. The bead starts at A, moving to the right with an initial velocity v. The wire is frictionless between A and D and between F and G, but there is friction between D and F. (For each statement select True, False, Greater than, Less than, Equal to, or Not enough information to tell.http:////d2vlcm61l7u1fs.cloudfront.net/media%2F62f%2F62f71b78-00b4-43a8-a92b-de3a1b48521b%2Fphp3BwzEE.png
http:////d2vlcm61l7u1fs.cloudfront.net/media%2F87b%2F87b2fab7-a0ac-403b-89aa-426164f8224c%2Fphp6TF9ue.png

Homework Equations


KE= (1/2)mv^2
PE = mgh

The Attempt at a Solution



a) The bead is sliding down with gravity with no friction, so the speed will increase. Answer = True?

b) The velocity of the bead at D is higher than at F because before D, there is no friction, but after D to F, Friction is present. Because the velocity is smaller at F than D, the KE is smaller at F than at D. Answer = Greater than?

c) There is no friction present and its a horizontal surface so speed remains constant form D to E. Answer = Equal?

d) Conservation of energy. Answer = Equal

I'm not sure if these are correct. Any help would be greatly appreciated. Thanks![/B]
 

Attachments

  • Screen Shot 2016-10-16 at 2.44.26 PM.png
    Screen Shot 2016-10-16 at 2.44.26 PM.png
    14.4 KB · Views: 761
Physics news on Phys.org
Hi Elliott98 and welcome to PF.

We cannot see the statements that are supposed to be True or False. The pictures did not load. Try reloading them or perhaps you can enter them by hand.
 
  • Like
Likes   Reactions: Elliott98
Elliott98 said:
The velocity of the bead at D is higher than at F because before D, there is no friction, but after D to F, Friction is present.
What else might affect the velocity over that segment? Would the speed at F be the same as at D if there were no friction in between?
 
  • Like
Likes   Reactions: Elliott98
kuruman said:
Hi Elliott98 and welcome to PF.

We cannot see the statements that are supposed to be True or False. The pictures did not load. Try reloading them or perhaps you can enter them by hand.
I can't seem to be able to upload them so here they are:

a) Between A and B, the speed increases.
b) The bead's kinetic energy at D is ... it's kinetic energy at F.
c) The speeds at D and E are equal.
d) The total energy of the bead at B is ... the total energy at D.
 
a) Correct.
b) Think again in view of @haruspex's post#3.
c) Correct.
d) Correct.
 
  • Like
Likes   Reactions: Elliott98
Elliott98 said:
I can't seem to be able to upload them so here they are:

a) Between A and B, the speed increases.
b) The bead's kinetic energy at D is ... it's kinetic energy at F.
c) The speeds at D and E are equal.
d) The total energy of the bead at B is ... the total energy at D.
Actually, the preferred way to post is with text rather than images of textual material.

Also, it's helpful to post full size images, so here is the one image of yours that survived - now in full size.
screen-shot-2016-10-16-at-2-44-26-pm-png.107616.png

and your answers ...
Elliott98 said:
a) The bead is sliding down with gravity with no friction, so the speed will increase. Answer = True?

b) The velocity of the bead at D is higher than at F because before D, there is no friction, but after D to F, Friction is present. Because the velocity is smaller at F than D, the KE is smaller at F than at D. Answer = Greater than?

c) There is no friction present and its a horizontal surface so speed remains constant form D to E. Answer = Equal?

d) Conservation of energy. Answer = Equal
 
kuruman said:
a) Correct.
b) Think again in view of @haruspex's post#3.
c) Correct.
d) Correct.
For (c): There is friction in that segment.
 
SammyS said:
For (c): There is friction in that segment.

Oops, I made a mistake. Thanks for pointing it out.

So I have a) True
b) Sorry, I'm a bit confused. The formula for kinetic energy is = 1/2 mv^2. So that mass at D is the same as at F so that doesn't change. For velocity, it will decrease because of friction? Or the velocity will increase because the beed is going down the slope, but friction will work against it so it will remain the same?
c) False, (because there is friction, the bead will slow down, so the speeds aren't equal)
d) Equal to.

Thanks for all the help!
 
Elliott98 said:
b) Sorry, I'm a bit confused. The formula for kinetic energy is = 1/2 mv^2. So that mass at D is the same as at F so that doesn't change. For velocity, it will decrease because of friction? Or the velocity will increase because the beed is going down the slope, but friction will work against it so it will remain the same?
You seem to be listing two possibilities there. Can you think of a third? (or a fourth).
 

Similar threads

  • · Replies 23 ·
Replies
23
Views
5K
  • · Replies 40 ·
2
Replies
40
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
7K
  • · Replies 16 ·
Replies
16
Views
16K
  • · Replies 5 ·
Replies
5
Views
5K