Physics I question Skydiver falling

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    Falling Physics
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The discussion focuses on calculating the terminal speed of a 79 kg skydiver modeled as a rectangular box falling feet first. The user attempted to use the drag equation but expressed uncertainty about their calculations, particularly regarding the coefficient of drag and the area used. They converted the skydiver's weight from kilograms to newtons correctly but questioned their application of the drag formula. Clarification was sought on whether to use 1/4 or 1/2 for the drag coefficient in the equation. The conversation emphasizes the importance of correctly identifying the drag formula and ensuring accurate area calculations to determine terminal velocity.
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Homework Statement



A 79 kg skydiver can be modeled as a rectangular "box" with dimensions 25 cm x 39 cm x 1.8 m.

What is his terminal speed if he falls feet first?


Homework Equations







The Attempt at a Solution



So I am not sure what I am doing wrong, here is what i did.

D= 1/4 av2 = .25(.25 x .39)= .020

skydiver's weight i took from kg to N which ended up being 774.2

then i did 774.2/.020 and did square root, and i ended up with 196.7, apparently it is saying this is not the right answer, did i do this correctly!? help! :(
 
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What formula are you using? isn't the formula for drag \frac{1}{4}\rho ADv^2 maybe \frac{1}{2}\rho ADv^2 (Its late and I feel lazy to find out which)

where \rho is the density of air, A is the area of the object and D is the coefficient of drag
 
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