Physics: Inclined Plane With Wheels

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SUMMARY

The discussion focuses on a physics problem involving a 4 kg block on a 37-degree inclined plane with wheels, where the coefficient of static friction is 0.3 and sliding friction is 0.2. The problem requires calculating the force needed to accelerate the system at 1.5 m/s² and the tension in the rope. The solution involves applying Newton's second law (F=ma) and understanding the relationship between normal force and friction. Additionally, the discussion addresses the conditions under which the normal force on the block becomes zero.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Knowledge of static and kinetic friction coefficients
  • Familiarity with inclined plane physics
  • Ability to resolve forces into components
NEXT STEPS
  • Study the effects of friction on inclined planes using different coefficients
  • Learn about the dynamics of systems with multiple bodies and forces
  • Explore the concept of normal force and its implications in physics problems
  • Investigate the role of tension in systems involving pulleys and ropes
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and inclined plane problems, as well as educators looking for examples of force analysis in multi-body systems.

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Homework Statement



A 4 kg block rests on 37 degrees inclined plane with wheels, held in place by a light rope which is parallel to the plane. The coefficient of static friction is 0.3 and the coefficient of sliding friction is 0.2. The mass of the inclined plane (with wheels) is 16 kg.

A.) The block is attached with the rope to the incline and the surfaces are treated with a magical substance that eliminates friction. The wheels are unlocked, and a horizontal force is applied to the plane so that it rolls and accelerates to the right at 1.5 m/s/s.

I. Find the magnitude of the force required to the make the system accelerate.
II. Find the tension in the rope.

B.) With the conditions in part A, find the minimum horizontal force applied to the apparatus that reduces the normal force of the plane on the 4 kg block to zero.

Homework Equations



F=ma
ƒ(friction)=\muN


The Attempt at a Solution



A.) For I.) F_x = F=ma so F=(16 + 4)(1.5) = 30 N
Is the question asking how hard to push the whole inclined plane with the box in order for it to accelerate at 1.5 m/s/s?

For II.) F_y=N-mgcos\theta=0 so N=mgcos\theta
and F_x=T-mgsin\theta=ma so T=mgsin\theta+ma
Are these the correct equations to use?


B.) ƒ=\muN and ƒ=0 but I don't really understand what the question is asking. The normal force on the box would be N=mgcos\theta, but how could a horizontal force make a vertical force equal to zero.

Thanks
 
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Can you draw the figure?
In the statement of the problem you have given the μs and μk.
But in A you mention that the surface is frictionless. What it means? I can't imagine the position of the rope.
 

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