1. The problem statement, all variables and given/known data Find the reaction forces of A and B. Uniform bar with a mass of 100kg/m supported by a pin and a roller. [tex]\Theta[/tex] = 60 g=9.81m/s2 [URL]http://img340.imageshack.us/i/mechanicsproblem.jpg/[/URL] http://img340.imageshack.us/i/mechanicsproblem.jpg/ 2. Relevant equations Moment/torque = Force*Displacement Sum of MA=0 (moment about point A) Sum of FY=0 Sum of FX=0 3. The attempt at a solution Taking M about point A. (Counter-clockwise as +ve) 9BY - (1500N*7m) - (2400N*sin(60) * 3.5m) - [100kg/m*9m*9.81m/s2*(1/2*9m)]=0 9BY = 57,505N BY = 6.389kN B = 6.389kN Sum of FY=0 AY + BY - 2.4kN*sin(60) - 1.5kN - (W=8.829kN) = 0 AY = 6.018kN Sum of FX=0 AX - 2.4kN*cos(60) = 0 AX = 1.2kNWould like to verify whether my attempt at the question is correct, as well as my free body diagram.