Physics: Multiplying Unit vectors

AI Thread Summary
The discussion centers on the multiplication of unit vectors, specifically the cross product. The user is confused about calculating (i^×j^)×k^ and mistakenly believes it simplifies to k^×k^. Key points include the need to understand the properties of the cross product, such as bilinearity and anti-commutativity. It is clarified that the cross product of a vector with itself, like k^×k^, equals zero, not k^ squared or -1. Understanding these vector multiplication rules is essential for accurate calculations in physics.
RaeMarine
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[Moderator note: Post moved from New Member Introductions forum, so no template]

I am having trouble understanding how to multiply unit vectors. I know that: (please excuse the notation)
i^×j^ = k^
j^×k^ = i^
k^×i^ = j^

The question I am stuck on is: What is (i^×j^)×k^?
So far I have (i^×j^) = k^, which would mean the above equation turns into k^×k^. I am supposed to represent the answer in unit vector form, but the only answers I can come up with are k^ squared or -1... What am I missing? All help is appreciated!
 
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RaeMarine said:
I am having trouble understanding how to multiply unit vectors. I know that: (please excuse the notation)
i^×j^ = k^
j^×k^ = i^
k^×i^ = j^

The question I am stuck on is: What is (i^×j^)×k^?
So far I have (i^×j^) = k^, which would mean the above equation turns into k^×k^. I am supposed to represent the answer in unit vector form, but the only answers I can come up with are k^ squared or -1... What am I missing? All help is appreciated!
Don't ask technical questions in your Introduction post.

You should learn some basic facts about dot products and cross products of unit vectors.

https://en.wikipedia.org/wiki/Cross_product
 
What can I ask in my introduction post?
 
RaeMarine said:
What can I ask in my introduction post?
You shouldn't ask anything. The purpose of an introduction post is to introduce yourself.
 
RaeMarine said:
I am having trouble understanding how to multiply unit vectors. I know that: (please excuse the notation)
i^×j^ = k^
j^×k^ = i^
k^×i^ = j^
If that is all you know then you don't know enough to calculate anything else! You would also need to know that the "cross product" of two vectors is "bilinear" meaning (au^+ bv^) x w^= a(u^xw^)+ b(v^xw^) and that the cross product is "anti-commutative" meaning that u^xv^= -v^xu^

The question I am stuck on is: What is (i^×j^)×k^?
So far I have (i^×j^) = k^, which would mean the above equation turns into k^×k^. I am supposed to represent the answer in unit vector form, but the only answers I can come up with are k^ squared or -1... What am I missing? All help is appreciated!
There are three different kinds of "multiplication" defined for vectors, the "scalar product", of a scalar with a vector, returning a vector, the "dot product" (also called "inner product"), of two vectors, returning a scalar, and the "cross product", that you are talking about here, of two vectors, returning a vector. The terminology "k^ squared" is ambiguous because that would be a product of two vectors which could be either the dot product or the cross product. To find the cross product of k with itself, use the fact that "u^xv^= -v^xu^" with both u^ and v^ equal to k^ that gives k^xk^= -k^xk^. What does that tell you?
 
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