Physics-Using vectors to find the components

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The discussion focuses on calculating the east and north components of a displacement vector for a trapper walking 6.2 km at an angle of +45 degrees. The east component is determined to be 4.38 km using the formula $6.2 \times \cos(45^{\circ})$, and the north component is also 4.38 km using $6.2 \times \sin(45^{\circ})$. The next question involves calculating the additional distance the trapper would need to walk if she traveled along these component displacements, which requires summing the components and subtracting the original distance of 6.2 km.

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cbarker1
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Hello Everybody,

A trapper walks a 6.2 km straight-line distance from the cabin to the lake, beginning to the lake has an angle of +45 degrees. Determine the east and north components of her dispacement vector.

Work:
E component: $6.2\times\cos\left({45^{\circ}}\right)$ = 4.38

N Component:$6.2\times\sin\left({45^{\circ}}\right)$=4.38

I have troubles to next question:
How many more kilometers would the trapper have to walk if she walked along the component displacements?
 
Last edited:
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You've found the length of the components, so if the trapper walks along the components, that distance would be the sum of the two components. To answer the question you would then need to subtract the actual distance walked from this sum. :)
 

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