Picard Iteration, with a 2nd order ODE

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To perform Picard iterations on the second-order ODE y'' = 6y^2 with initial conditions y(0) = 0 and y'(0) = -2, it is essential to transform the equation into a first-order system. This can be achieved by substituting p = y' and recognizing that y'' can be expressed as dp/dy. By doing so, the problem simplifies into a format suitable for applying Picard iterations, allowing for the iterative solution process to commence. Understanding this transformation is crucial for effectively tackling the problem. The discussion emphasizes the importance of substitution in solving higher-order differential equations using Picard's method.
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Homework Statement



Ive been told to perform 2-3 Picard Iterations on the following problem

Homework Equations



y'' = 6y^2

With initial conditions:

y(0) = 0
y'(0)= -2

The Attempt at a Solution



In class we've gone through how to perform picard iterations and it has been easy so far... however this is the first time it has had a second order term at the front. Through internet searches and reading our given notes, I am still not sure how to treat this so I can't really start to try and solve it...

Would anyone be able to give me a nudge in the right direction?Thanks in advance
 
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It's just substitution, i.e f(y, y', y'')-> f(y, p, pdp/dy).
You assume there exists a p: p = y', pdp/dy = y'' and at the end you back substitute for y. This transforms a second order ODE into a first order ODE.
 
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