Piece of iron put into container with ice

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Homework Help Overview

The problem involves a piece of iron at a high temperature being placed in a container with ice at 0 degrees Celsius. Participants are exploring the thermal interactions between the iron and the ice, specifically focusing on the state of the system after reaching thermal equilibrium and the calculation of entropy changes.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the heat balance between the iron and the ice, questioning whether all the ice melts and what the final equilibrium temperature will be. There are attempts to define coefficients to describe the melting of ice and the heat transfer involved.

Discussion Status

Some participants are exploring different scenarios regarding the melting of ice and the final temperature of the system. There is acknowledgment of the complexity of heat flow involving both ice and liquid water, and some guidance has been offered regarding the understanding of energy transfer and equilibrium conditions.

Contextual Notes

Participants are working under the constraints of a homework problem, which may limit the information available for a complete analysis. The discussion includes assumptions about the state of the system and the behavior of materials at different temperatures.

Lukasz Madry
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Homework Statement


We put 1kg iron of temperature 100 Celsius into container with 1kg of ice, temperature 0 Celsius. What is state of the system after reaching equilibrium? Calculate change of entropy.

Coefficient of melting of ice (c_L) is 330 kJ/kg, coefficient of heat transfer of iron (c_I) is 450 J/(kg*K).

Homework Equations


I don't really know. Heat balance, for sure. Entropy equation - Q = ∫ T dS.
S = c ln(T_f/T_i)
But I'm sure I'm missing something crucial.

The Attempt at a Solution


I tried to compute heat balance:

C_I ( 100 - T_f) = c_L

but this does not work, obviously, since leads to T_f = 100 - c_L/c_I = 100 - 733 which is far below zero temperature.

Another attempt - assume that only part of ice was melted. Let k = c_I 100 / c_L be coefficient that describes how much ice was melted into water. In this case, entropy would be:

S_{iron} = c_I ln(273/373)
S_{ice} = k c_L/273

after substition we can find that it's sum is greater than zero, which is expected.

Is this close to being correct?
 
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So the first thing that I would try to figure is if all the ice melted or not. It seems you determined the answer to that. If you have a container which has ice and liquid water and a piece of iron at equilibrium, what temperature do you think the whole thing will be? If the iron and water are different temperatures, is it at equilibrium? Once you figure the final temperature, then you can figure how much heat transferred from the iron, then go from there.
 
Essentialy, energy will flow from iron to ice until iron reaches temperatures of ice OR ice melts down. In this case, iron reaches 0 Celsius way before ice melts down. My only gripe with this is liquid water that keeps appearing - at the beginning it has temperature of ice, but is in contact with iron. It should make heat flow from iron not only to ice, but to this water too. However, ultimately this heat should also reach ice, since ice has temperature of 0 until it totally melts down.

This means that whole thing will be at the temperature of 0 Celsius, and there will be ice, liquid water and iron in the system. Proportions of ice to liquid water are determined by k coefficient I defined in the first post.
Is this correct?
 
Thank you for Your help
 

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