Piezoelectric effect- tube scanner

  • Thread starter solas99
  • Start date
  • #1
69
1

Main Question or Discussion Point

Hi,

i have been working on this problem for a while. i just need some guidance.

the question is: design a ztube scanner suitable for displacing ±1 micron displacement at 200V.

i am using this equation:

ΔL=([d]_{}[/31]×V×L)/t
ΔL=(d31 ×L×V)/t

ΔL=change in length = 1micron
d31=piezo strain constant (usually in pico range [10]^{}[/-12]
V=applied voltage
L=length
t=thickness (for a tube-- Outer diameter - inner diameter (OD-ID))

Rearranging the equation:

[ΔL]\frac{}{}[/V]=[L]\frac{}{}[/t×[d]_{}[/31]]

ΔL/V= L/(d×d31)


∴[ΔL]\frac{}{}[/V]=1micron/200=5nm/v

Im currently using this link.
http://www.physikinstrumente.com/en/products/prdetail.php?sortnr=400800.00


I am trying to solve it by,
choosing V=200V
ΔL= 1micron

∴[ΔL]\frac{}{}[/V]=
ΔL/V=1micron/200=5nm/v

how do i proceed after this step? i tried picking a value for [d]_{}[/31]=1.27[10]^{}[/-12]
but then i got stuck on picking realistic diameters for the piezo tube.

I am also wondering is the d31 chosen arbitrary, or its specific to the material being used, and so is it a parameter i cant control in the equation.
Usually d31 is given in pico scale.
L=1-70mm
Max diameter__ OD=78mm, ID=70mm
MIn diameter__ OD=2mm, ID0.8mm
d31= ?

i might be missunderstanding the question or equation.

thnks
 

Answers and Replies

  • #2
UltrafastPED
Science Advisor
Gold Member
1,912
216
d31 (and d33) are material parameters. You have to know the value for the material that you are using.
 

Related Threads on Piezoelectric effect- tube scanner

  • Last Post
Replies
2
Views
687
  • Last Post
Replies
2
Views
750
Replies
2
Views
534
Replies
2
Views
7K
Replies
2
Views
7K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
9
Views
4K
  • Last Post
Replies
4
Views
5K
Replies
2
Views
1K
Top