: Planck/Einstein and death of the universe

  • Thread starter Thread starter KCvolunteer07
  • Start date Start date
  • Tags Tags
    Death Universe
AI Thread Summary
The discussion explores the relationship between Planck's quantum mechanical equation and Einstein's conservation of energy law in the context of the universe's heat death. The heat death is explained through the second law of thermodynamics, which states that entropy increases over time, leading to energy becoming evenly distributed and unable to perform work. Planck's equation indicates that energy is exchanged in discrete quanta, while Einstein's law emphasizes that energy can only change forms, not be created or destroyed. Together, these principles suggest that as energy transforms, it will ultimately reach a state of equilibrium, resulting in the universe's heat death. This highlights the interconnectedness of quantum mechanics, thermodynamics, and cosmology.
KCvolunteer07
Messages
1
Reaction score
0
I don't expect anyone to get this, but it's worth a shot. Maybe someone will impress me.

Mathematically relate Planck's Quantum mechanical equation and Einstein's equation of the law of conservation of energy to the heat death of the universe (Remember that the head death of the universe implies that all mass is eventually converted to energy-aka-burning up. In other words, use the 2nd law of thermodynamics).

I know all of the equations, but I'm clueless on how to relate them. Please help!
 
Physics news on Phys.org
The heat death of the universe is based on the second law of thermodynamics, which states that entropy (disorder/randomness) increases over time. This means that all energy in the universe will eventually become evenly distributed and unable to do any work. Planck’s quantum mechanical equation states that energy can only be exchanged in discrete packets or quanta and Einstein’s equation of the law of conservation of energy states that energy cannot be created or destroyed, but can be converted from one form to another. This means that as energy is converted from one form to another, it will eventually become evenly distributed, as per the second law of thermodynamics, leading to a state of equilibrium or ‘heat death’.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top