Please help with a friction problem (due tomorrow)

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To determine the coefficient of friction (μ) between a 22kg chair and the floor, the work done (15J) to push it 1.8m is analyzed. The formula used is μ = W / (M * g * D), where W is work, M is mass, g is gravitational acceleration (9.8 m/s²), and D is distance. Substituting the values gives μ = 15 / (22 * 9.8 * 1.8), resulting in a coefficient of friction of approximately 0.46. The initial mention of μ = 0.04 appears to be incorrect based on the calculations provided. Understanding these calculations is crucial for the upcoming test.
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Determine the coefficient of friction between a 22kg chair and the floor if it requires 15J to push it 1.8m (We're doing a Kinetic and Potential energy unit)

Answer for mu is .04, but can you help me in getting there, we have a test tomorrow!


Thanks in advance!
 
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StevieRayT said:
Determine the coefficient of friction between a 22kg chair and the floor if it requires 15J to push it 1.8m (We're doing a Kinetic and Potential energy unit)

Answer for mu is .04, but can you help me in getting there, we have a test tomorrow!Thanks in advance!
This is not were you post homework questions. To answer your problem though.

F = ukN
uk = F / MG
W = D * F
F = W / D
uk = W / MGD
uk = (15) / (22)(9.8)(1.8)
uk = 0.46
 

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